400A - Inna and Choose Options - CodeForces Solution

a=int(input())
one=two=three=four=six=0
o=["a"]*a
i=0
for i in range (a):
    b=input()
    c=list(b)
    for j in range (6):
        if c[j]==c[j+6]=="X":
            six=1
            break
        else:
            six=0
            j=j+1
            

    for j in range (4):
        if c[j]==c[j+4]==c[j+8]=="X":
            four=1
            break
        else:
            four=0
            j=j+1
            
    
    for j in range (3):
        if c[j]==c[j+3]==c[j+6]==c[j+9]=="X":
            three=1
            break
        else:
            three=0
            j=j+1


    for j in range (2):
        if c[j]==c[j+2]==c[j+4]==c[j+6]==c[j+8]==c[j+10]=="X":
            two=1
            break
        else:
            two=0
            j=j+1
         
    for j in range (1):
        if c[j]==c[j+1]==c[j+2]==c[j+3]==c[j+4]==c[j+5]==c[j+6]==c[j+7]==c[j+8]==c[j+9]==c[j+10]==c[j+11]=="X":
            one=1
            break
        elif c[j]==c[j+1]==c[j+2]==c[j+3]==c[j+4]==c[j+5]==c[j+6]==c[j+7]==c[j+8]==c[j+9]==c[j+10]==c[j+11]=="O":
            one=two=three=four=six=2
        else:
            one=0
    
    if one==1:
        o[i]="6 1x12 2x6 3x4 4x3 6x2 12x1"
    elif two==1 and three==1 and four==1 and six==1:
        o[i]="5 1x12 2x6 3x4 4x3 6x2"
    elif two==1 and four==1 and six==1 and three==0:
        o[i]="4 1x12 2x6 3x4 6x2"
    elif three==1 and four==1 and six==1 and two==0:
        o[i]="4 1x12 2x6 3x4 4x3"
    elif three==1 and six==1 and two==0 and four==0:
        o[i]= "3 1x12 2x6 4x3"
    elif two==1 and three==0 and four==1 and six==0:
        o[i]= "3 1x12 3x4 6x2"
    elif two==0 and three==0 and four==1 and six==0:
        o[i]= "2 1x12 3x4"
    elif two==0 and three==0 and four==1 and six==1:
        o[i]= "3 1x12 2x6 3x4"
    elif two==0 and three==0 and four==0 and six==1:
        o[i]= "2 1x12 2x6"
    elif two==0 and three==0 and four==0 and six==0:
        o[i]= "1 1x12"
    elif two==2 and three==2 and four==2 and six==2:
        o[i]="0"
    else:
        o[i]= "miscalculated"
for i in range (a):
    print( o[i] )